Oxidation number of carbon in $H_{2} C_{2} O_{4}$ is

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-2

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Solution

The correct option is B 3
$H_{2}_{2} O_{4}$
$2 + 2 x - 2 \times 4 = 0; 2 x = 8 - 2 = 6$
$x = \frac{6}{2} = + 3$ .

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