Oxidation number of cobalt in $K [C o {(C O)}_{4}]$ is:

+ 1

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+ 3

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- 1

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- 3

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Solution

The correct option is C $- 1$
Let oxidation number of $C o$ be $x$ and $C O$ has zero oxidation number. The oxidation number of $K$ is +1.

So, $1 + x = 0$ .

$x = - 1$ .

The oxidation number of cobalt is -1.

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