Oxidation number of $C r$ in $[C r [N H_{3}]_{4} C l_{2}]^{+}$ is ____.

+ 4

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+ 2

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+ 3

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+ 6

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Solution

The correct option is C $+ 3$
Oxidation number of $C r$ in $[C r [N H_{3}]_{4} C l_{2}]^{+}$ is $+ 3$
$x + (4 \times 0) + (- 1 \times 2) = + 1$
$x - 2 = + 1$
$x = + 3$

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