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Electronic Configuration and Oxidation States

Oxidation num...

Question

Oxidation number of Cr in the following complex is- $[C r (E D T A)]^{-}$ :

A

3

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B

6

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C

4

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D

5

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Solution

The correct option is B 3
EDTA has 4 negative charges.

So the oxidation number of Cr is
x-4=-1

x=3

Option A is correct.

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