Oxidation number of Fe in [Fe(CN)6]−3,[Fe(CN)6]−4 respectively would be :
A
+3, +2
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B
+3, +3
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C
+3, -2
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D
+2, +2
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Solution
The correct option is A +3, +2 Let oxidation number of Fe be 'x' in [Fe(CN)6]3− charge on CN−=−1 ⇒x−6=−3 ⇒x=+3 Let oxidation number of Fe be 'x' in [Fe(CN)6]4− charge on CN−=−1 ⇒x−6=−4 ⇒x=+2