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Question

Oxidation number of Fe in [Fe(CN)6]3,[Fe(CN)6]4 respectively would be :

A
+3, +2
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B
+3, +3
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C
+3, -2
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D
+2, +2
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Solution

The correct option is A +3, +2
Let oxidation number of Fe be 'x' in [Fe(CN)6]3
charge on CN=1
x6=3
x=+3
Let oxidation number of Fe be 'x' in [Fe(CN)6]4
charge on CN=1
x6=4
x=+2

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