Oxidation number of iodine varies from:

- 1

+ 1

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- 1

+ 7

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+ 3

+ 5

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- 1

+ 5

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Solution

The correct option is B $- 1$ to $+ 7$
Various oxidation numbers of Iodine are -1, 0, +1, +3, +5, +7.
So, Iodine shows -1 to +7 oxidation state.

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Similar questions

when $S O_{2}$ is passed in a solution of potassium iodate, the oxidation state of iodine changes from :

I_{2} \to I O_{3}^{-} + I^{-}

B r_{2} \to B r O_{3}^{-}

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