Question

Oxidation number of ${}^{\prime }{N}^{\prime }$ in $N_{3}H$ (hydrazoic acid) is:

• A. $-\frac{1}{3}$
• B. $+3$
• C. $0$
• D. $-3$

Answer 1

Answer: (A)

$-\frac{1}{3}$

The oxidation state of $N$ in $N_{3}H$ (hydrazoic acid) is:

$\Rightarrow 3x+1=0$

$\Rightarrow 3x=-1$

$\Rightarrow x=-\frac{1}{3}$

Hence, option $A$ is correct.