Question

Oxidation number of nitrogen "$N$" in $N_2{H}_5^{+}$​ is :

• A. $-1$
• B. $+3$
• C. $-2$
• D. $+1$

Answer 1

The correct option is C $-2$

Let the oxidation number of nitrogen be $x.$
Oxidation number of $H=+1$
$\left(N_2{H}_5{}^{+}\right)$:
$2\times x+5\times 1=+12x+5=1or,2x=-4x=-2$
Thus Oxidation number of N in$\left(N_2{H}_5{}^{+}\right)$ is $-2.$