Oxidation number of S in $S O_{4}^{2 -}$ :

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-2

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Solution

The correct option is D 6
Let oxidation state of S in $S O_{4}^{2 -} = x$
$∴ x + (4 \times - 2) = - 2$
or $x - 8 = - 2$ $∴$ $x = + 6$

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