Find the oxidation number of $S$ in ${S O_{4}}^{2 -}$ ion?

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Solution

Let the oxidation number of $S$ be $x$ .
We know that, Ox. no. of $O$ $= - 2$
So, Ox. no. S $+$ $4$ (Ox. no. $O$ ) $= - 2$
or $x + 4 (- 2) = - 2$
or $x - 8 = - 2$
or $x = + 8 - 2 = + 6$
The oxidation number of $S$ in $S O_{4}^{2 -}$ ion is $+ 6$ .

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