Oxidation state for the underlined atom in $K_{2} C r - - - O_{4}$ is:

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Solution

The correct option is B 6
Oxidation state for the underlined atom in $K_{2} C r - - - O_{4}$ is +6.
Let, $X$ be the oxidation state of $C r$ .
$2 (+ 1) + X + 4 (2 -) = 0 2 + X - 8 = 0 X - 6 = 0 X = + 6$

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