Oxidation state of chromium in its compound having orange coloured solution is :

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Solution

Oxidation state of chromium in its compound having orange coloured solution is $+ 6$ as $K_{2} C r_{2} O_{7}$

$K = + 1$

$O = - 2$

$C r = + 6$

$2 K^{+}$ + $C r_{2} O_{7}^{- 2}$
$C r_{2} O_{7}^{- 2}$ $=$ $2 x + 7 \times (- 2) = - 2$
$2 x = 12$
$x = 6$

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Oxidation state of chromium in its compound having orange coloured solution is :

Oxidation state of chromium in its compound having orange coloured solution is +6 as K2Cr2O7 K=+1 O=−2 Cr=+6 2K+ + Cr2O−27Cr2O−27 = 2x+7×(−2)=−2 2x=12 x=6

Oxidation state of chromium in its compound having orange coloured solution is $+ 6$ as $K_{2} C r_{2} O_{7}$

$K = + 1$

$O = - 2$

$C r = + 6$

$2 K^{+}$ + $C r_{2} O_{7}^{- 2}$
$C r_{2} O_{7}^{- 2}$ $=$ $2 x + 7 \times (- 2) = - 2$
$2 x = 12$
$x = 6$