Oxidation state of iodine in iodic acid is:

+ 1

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+ 3

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+ 5

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+ 7

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Solution

The correct option is D $+ 5$
Iodic acid is $H I O_{3}$ .
$1 (+ 1) + x + 3 (- 2) = 0$
$x = 6 - 1$
$x - + 5$
Hence option C is correct.

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