Oxidation state of molybdenum in $M o_{2} C l_{8}^{4 -}$ ion is

+ 4

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- 4

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+ 1

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+ 2

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Solution

The correct option is D $+ 2$
Let the oxidation state of molybdenum in $M o_{2} C l_{8}^{4 -}$ be $x$ .
Therefore, $2 x - 8 = - 4 ⟹ x = + 2$ .

So, the oxidation state of $M o$ is +2.
Correct option is 'D'

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