Oxidation state of oxygen in Tribromo Octaoxide (Br3O8) is Options: 16/3 –2 +2 -16/3

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B r_{3} O_{8}

16

- 2

The oxidation state of oxygen in $K O_{3}$ , $N a_{2} O_{2}$ are respectively :

\begin{matrix} {cos}^{4} \frac{π}{16} + {sin}^{4} \frac{π}{16} - {sin}^{2} \frac{π}{16} {cos}^{2} \frac{π}{16} + {cos}^{4} \frac{3 π}{16} + {sin}^{4} \frac{3 π}{16} - {sin}^{2} \frac{3 π}{16} {cos}^{2} \frac{3 π}{16} \end{matrix}

K O_{3}

N a_{2} O_{2}

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