Oxidation state of S in $[H S O_{4}]^{-}$ is

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-2

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Solution

The correct option is C 6
We know,
Generally O. S. (O) = -2
O. S. (H) =+1
Now,
Therefore,
$[H S O_{4}]^{-} \Rightarrow 1 + n + 4 (- 2) = - 4 \Rightarrow S = 8 - 2 = + 6$

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