Oxidation state of $S$ in ${S O_{4}}^{2 -}$ is:

+ 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $+ 6$
Let oxidation state of $S$ is x.

and oxidation state of $O$ in $S O_{4}^{2 -}$ is -2.

and the net charge on the compound is -2.

$∴ x + 4 (- 2) = - 2$

$x = + 6$ .

Suggest Corrections

Similar questions

S O_{4}^{2 -}

S F_{6}

{N a}_{2} S_{2} O_{3}

S

H_{2} S_{2} O_{8}

6

S

6

S O_{3}^{2 -}, S_{2} O_{4}^{2 -}

S_{2} O_{6}^{2 -}

S_{4} O_{6}^{2 -}, S_{2} O_{3}^{2 -}, S_{2} O_{8}^{2 -}, S_{2} O_{7}^{2 -}

Join BYJU'S Learning Program