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Question

Oxidation states of P in H4P2O6, H4P2O6, H4P2O7 are respectively:


A
+3, +5, +4
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B
+5, +3, +4
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C
+5, +4, +3
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D
+3, +4, +5
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Solution

The correct option is D +3, +4, +5
H4P2O5:4(1)+2x+5(2)=0
4+2x10=0
x=+3
H4P2O6:4(1)+2x+6(2)=0
x=+4
H4P2O7:4(1)+2x14=0
x=+5

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