Question

Oxidation states of $P$ in $H_4{P}_2{O}_6,H_4{P}_2{O}_6,H_4{P}_2{O}_7$ are respectively:

• A. +3, +5, +4
• B. +5, +3, +4
• C. +5, +4, +3
• D. +3, +4, +5

Answer 1

The correct option is D +3, +4, +5

$H_4{P}_2{O}_5:4\left(1\right)+2x+5(-2)=0$
$4+2x-10=0$
$x=+3$
$H_4{P}_2{O}_6:4\left(1\right)+2x+6(-2)=0$
$x=+4$
$H_4{P}_2{O}_7:4\left(1\right)+2x-14=0$
$x=+5$