Oxide, peroxide and superoxide - all the three can be formed by:

L i, K

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N a, K

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K, R b

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N a, C s

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Solution

The correct option is B $K, R b$
Usually Li and Na form oxide and peroxide, respectively. K, Rb and Cs form superoxides. But K and Rb can form oxide, per oxide and superoxde, respectively. Option C is correct.

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Similar questions

The correct order of reactivity of alkalimetals towards $H_{2}$ is

N a, L i, R b,

K

(L i^{\oplus}, N a^{\oplus}, K^{\oplus}, R b^{\oplus})

(L i^{⨁}, N a^{⨁}, K^{⨁}, R b^{⨁})

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