Oxygen exhibit $- 1$ oxidation state in:

O F_{2}

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H_{2} O_{2}

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H C 1 O

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H_{2} O

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Solution

The correct option is B $H_{2} O_{2}$
$O^{- 1}$ exist where there is peroxide linkage. Hence $H_{2} O_{2}$ (Hydrogen peroxide).
$H - O - O - H$

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Oxygen exhibit −1 oxidation state in:

The correct option is B H2O2O−1 exist where there is peroxide linkage. Hence H2O2(Hydrogen peroxide).H−O−O−H

Oxygen exhibit $- 1$ oxidation state in:

The correct option is B $H_{2} O_{2}$
$O^{- 1}$ exist where there is peroxide linkage. Hence $H_{2} O_{2}$ (Hydrogen peroxide).
$H - O - O - H$