Oxygen has an oxidation state of $+ 2$ in.

H_{2} O_{2}

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O F_{2}

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S O_{2}

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H_{2} O

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Solution

The correct option is B $O F_{2}$
Oxidation state of oxygen is always -2 except in peroxides,superoxides and when it reacts with fluorine.
In $H_{2} O_{2}$ ,oxidation state of $H$ is +1, so oxidation state of oxygen is -1.
In $O F_{2}$ ,oxidation state of $F$ is -1, so oxidation state of oxygen is +2.
In $S O_{2}$ and $H_{2} O$ ,oxidation state of oxygen is -2.
So B) is correct answer.

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Q. The oxidation state of oxygen in

H_{2} O_{2}

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Q. Write the formulae of the compounds with given oxidation number of the given elements

	Element	O.N	Compounds
(a)	O	+2	$O F_{2}$
(b)	O	-1	$H_{2} O_{2}$
(c)	O	-0.5	$K O_{2}$
(d)	S	-2	$H_{2} S$
(e)	S	+4	$S O_{2}$
(f)	S	+6	$S O_{3}$

Q. Oxidation state of oxygen in

H_{2} O_{2}

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Oxygen has an oxidation state of +2 in.

Oxygen has an oxidation state of $+ 2$ in.