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Standard XII

Chemistry

Elevation in Boiling Point

0.456 gram of...

Question

0.456 gram of an organic compound (Molecular mass = 100u) is dissolved in 31.14 grams of acetone. Calculate the boiling point of solution if Kb= 17.2 and boiling point of acetone = 56.2 degree Celsius.

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Solution

First calculate the elevation in boiling point,
Î”T_b = (K_f x w_b x 1000) / (M_B x w_A)
w_b = 0.45 g
w_A= 31.14 g
M_B = 100 x 1.66 x 10^-24 g.
Î”T_b = T_b^' - T_b
T_b^' = Î”T_b + T_b

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0.456 gram of an organic compound (Molecular mass = 100u) is dissolved in 31.14 grams of acetone. Calculate the boiling point of solution if Kb= 17.2 and boiling point of acetone = 56.2 degree Celsius.

First calculate the elevation in boiling point,Î”Tb = (Kf x wb x 1000) / (MB x wA)wb = 0.45 gwA = 31.14 gMB = 100 x 1.66 x 10-24 g.Î”Tb = Tb' - TbTb' = Î”Tb + Tb

First calculate the elevation in boiling point,
Î”T_b = (K_f x w_b x 1000) / (M_B x w_A)
w_b = 0.45 g
w_A= 31.14 g
M_B = 100 x 1.66 x 10^-24 g.
Î”T_b = T_b^' - T_b
T_b^' = Î”T_b + T_b