Question

18. Solve the following equation and check the result.

4(6z+8) −3(5𝑧+2)=35

Answer 1

Dear Student,

$$\begin{gathered} 4(6z+8)-3(5z+2)=35 \\ \Rightarrow 24z+32-15z-6=35 \\ \Rightarrow 9z+26=35 \\ \Rightarrow 9z=9 \\ \Rightarrow z=\frac{9}{9}=1 \end{gathered}$$

$$\begin{gathered} Letusverifytheresult \\ LHS=4(6z+8)-3(5z+2)=4(6\times 1+8)-3(5\times 1+\hspace{0.17em}2)=4\times \left(14\right)-3\left(7\right)=56-21=35 \\ RHS=35 \\ So,LHS=RHS(verified) \end{gathered}$$

Regards,