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Question

2 dice are thrown at the same time find the probability that the sum of the two numbers appearing on the top of the dice is more than 9

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Solution

When two dice are rolled,

Sample space, S = {(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}

So, n(S)= 36

Let "A" be the event of getting sum more than 9 on the dice.

Then A ={(4,6)(5,5)(5,6)(6,4)(6,5)(6,6)}
n(A)=6
P(A)=6/36=1/6

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