2 resistors A and B of resistances 4 and 6 ohm resp. r connected in parallel. The combination is connected across a 6 volt battery of negligible resistance.
calculate the power dissipated in each resistor

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Solution

The resistors are connected in parallel so the voltage across both the resistors will be same which is equal to 6 V.
So, current through the 4 Î© resistance is, I₄ = 6/4 = 1.5 A
The current through the 6 Î© resistance is, I₆ = 6/6 = 1 A
Power dissipated across the 4 Î© resistance is, P₄ = (1.5²)(4) = 9 W
Power dissipated across the 6 Î© resistance is, P₆ = (1²)(6) = 6 W

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