3^a = 4
4^b = 5
5^c = 6
6^d = 7
7^e = 8
8^f = 9
then abcdef = ?

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Solution

$9 = 8^{f} = (7^{e})^{f} = 7^{e f} = (6^{d})^{e f} = 6^{d e f} = (5^{c})^{d e f} = 5^{c d e f} = (4^{b})^{c d e f} = 4^{b c d e f} = (3^{a})^{b c d e f} = 3^{a b c d e f} S o, 9 = 3^{a b c d e f} 3^{2} = 3^{a b c d e f} a b c d e f = 2$

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Similar questions

12 a b + 9 a + 12 + 16 b =

(x + y + z)^{10}

The factor(s) of 12ab + 9a + 12 + 16b is/are:

3^{a} = 4, 4^{b} = 5, 5^{c} = 6, 6^{d} = 7, 7^{e} = 8

8^{f} = 9,

(a b c d e f)

$U = {x : x is a natural number & x \leq 10}$
$A = {a : a is an even number & a \leq 10}$
$B = {b : b is a prime number & b \leq 9}$

Then, $A^{c} \cap B^{c}$ is

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