$P_{4} O_{6}$ reacts with water to give :

H_{3} P O_{3}

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H_{4} P_{2} O_{7}

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H P O_{3}

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H_{3} P O_{4}

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Solution

The correct option is A $H_{3} P O_{3}$

When $P_{4} O_{6}$ reacts with water it gives phosphoric acid.
$P_{4} O_{6} (s) + 6 H_{2} O (l) \to 4 H_{3} P O_{3} (a q)$
Hence option A is correct.

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