a 0.2076g sample of an oxide of cobalt on analysis was found to contain 0.1476g cobalt. calculate the empirical formula of the oxide .[co=59amu]

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Solution

Amount of Co = 0.1476 g
Amount of O = (0.2076 – 0.1476) g = 0.06 g

Cobalt : Oxygen = 0.1476 : 0.06 (by mass)
= (0.1476/59) : (0.06/16) (by number)
= 2 : 3 (by number)

So empirical formula of the oxide is Co₂O₃

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a 0.2076g sample of an oxide of cobalt on analysis was found to contain 0.1476g cobalt. calculate the empirical formula of the oxide .[co=59amu]

Amount of Co = 0.1476 g Amount of O = (0.2076 – 0.1476) g = 0.06 g Cobalt : Oxygen = 0.1476 : 0.06 (by mass) = (0.1476/59) : (0.06/16) (by number) = 2 : 3 (by number) So empirical formula of the oxide is Co2O3

Amount of Co = 0.1476 g
Amount of O = (0.2076 – 0.1476) g = 0.06 g

Cobalt : Oxygen = 0.1476 : 0.06 (by mass)
= (0.1476/59) : (0.06/16) (by number)
= 2 : 3 (by number)

So empirical formula of the oxide is Co₂O₃