A 40 μF capacitor is charged by 220 V supply voltage. Then, this charged capacitor is connected across an uncharged capacitor of capacitance 60 μF.
The final potential difference across the combination is

Open in App

Solution

Given, C₁= 40 $μ F = 40 \times 10^{- 6} F$
V₁ = 220 volts
C₂ = $60 μ F = 60 \times 10^{- 6} F$
V₂ = 0 volts
Common potential, V = ?
The charge flows from one capacitor at higher potential to the other at lower potential till their potentials become equal. The common potential reached is given by :
$V = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}} V = \frac{40 \times 10^{- 6} \times 220}{(40 + 60) \times 10^{- 6}} = 88 v o l t s$

Suggest Corrections

Similar questions

Q. A capacitor of capacity

C_{1}

, is charged by connecting it across a battery of e.m.f.

V_{0}

. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity

C_{2}

. The potential difference across this combination is :

Q. A capacitor

C_{1}

is charged to a potential difference

V

. The charging battery is then removed and the capacitor is connected to an uncharged capacitor

C_{2}

. The potential difference across the combination is

A 100 pF capacitor is charged to a potential difference of 24 V. It is connected to an uncharged capacitor of capacitance 20 pF. What will be the new potential difference across the 100 pF capacitor ?

A 10 μ F

capacitor is fully charged to a potential difference of

50 V

. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes

20 V

. The capacitance of the second capacitor is

Q. A capacitor of capacity

C_{1}

is charged upto potential

V

volt and then connected in parallel to an uncharged capacitor of capacity

C_{2}

. The final potential difference across each capacitor will be :

Join BYJU'S Learning Program

A 40 μF capacitor is charged by 220 V supply voltage. Then, this charged capacitor is connected across an uncharged capacitor of capacitance 60 μF.The final potential difference across the combination is

A 40 μF capacitor is charged by 220 V supply voltage. Then, this charged capacitor is connected across an uncharged capacitor of capacitance 60 μF.
The final potential difference across the combination is