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Question

# A capacitor C1 is charged to a potential difference V. The charging battery is then removed and the capacitor is connected to an uncharged capacitor C2. The potential difference across the combination is

A
VC1C1+C2
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B
VC2C1+C2
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C
VC1C2C1+C2
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D
VC1+C2
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Solution

## The correct option is A VC1C1+C2Initial the charge Q=C1V.After removing the battery the both capacitors are in parallel. So total capacitance C=C1+C2Let the potential difference across the combination is V′now charge Q′=CV′=(C1+C2)V′As the total charge is conserved so Q=Q′⇒C1V=(C1+C2)V′∴V′=C1VC1+C2

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