Question

A capacitor of capacity $C_1$, is charged by connecting it across a battery of emf $V_o$. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity $C_2$. The potential difference across this combination is

• A. $\frac{C_2}{C_1+C_2}{V}_o$
  
• B. $\frac{C_1}{C_1+C_2}{V}_o$
  
• C. $\frac{C_1+C_2}{C_2}{V}_o$
  
  
• D. $\frac{C_1+C_2}{C_1}{V}_o$
  

Answer 1

The correct option is B $\frac{C_1}{C_1+C_2}{V}_o$


Battery is removed when it is fully charged
$Q=C_1{V}_o$
V across combination $=\frac{Q}{C_{net}}$
$V=\frac{C_1{V}_O}{C_1+C_2}$