A 80 kg man is parachuting and experiencing a downward acceleration of 2.5m/sec2 . mass of the parachute is 5 kg.what is the upward force on the parachute from air?what is the downward force on the parachute from the man?

Open in App

Solution

$F o l l o w i n g a r e t h e e q n o f m o t i o n o f d o w n w a r d m o t i o n o f p a r a c h u t e, (M + m) g - F_{u p} = (M + m) a . a n d d o w n w a r d f o r c e = (M + m) (g - a) = (80 + 5) (9.8 - 2.5) = 85 \times 7.3 = 620.5 N d o w n w a r d f o r c e = 620.5 N . T h e u p w a r d f o r c e a c t i n g = F_{u p} = M g = 80 \times (10 - 2.5) = 80 \times 7.5 = 600 N . F_{u p} = 600 N .$

Suggest Corrections

Similar questions

Q. An

80 k g

person is parachuting and is experiencing a downward acceleration of

2.8 m / s^{2}

. The mass of the parachute is

5 k g

. Find the upward force on the open parachute is: (Take

g = 9.8 m / s^{2})

Q. An

80 kg

person is parachuting and is experiencing a downward acceleration of

2.8 {m/s}^{2}

. The mass of the parachute is

5 kg

. The net force on the system (parachute+man) is (Take

{g=9.8 m/s}^{2}

Q. Given figure shows a man with a parachute. Name the force which is responsible for his downward motion. Will he come down with the same speed without the parachute?

Question 19

Fig. shows a man with a parachute. Name the force which is responsible for his downward motion. Will he come down with the same speed without the parachute?

Question 19

Fig. shows a man with a parachute. Name the force which is responsible for his downward motion. Will he come down with the same speed without the parachute?

Join BYJU'S Learning Program

A 80 kg man is parachuting and experiencing a downward acceleration of 2.5m/sec2 . mass of the parachute is 5 kg.what is the upward force on the parachute from air?what is the downward force on the parachute from the man?

Following are the eqn of motion of downward motion of parachute,M+mg-Fup=M+ma.and downward force = M+m(g-a)=80+59.8-2.5=85×7.3=620.5N downward force =620.5N.The upward force acting = Fup=Mg=80×10-2.5=80×7.5=600N. Fup =600N.