Question

a athlete throws a javelin with v=20 m/s at an angle 15 with horizontal.how far the javelin will hit the gournd.

Answer 1

$$\begin{gathered} Thisisthecaseofangularprojectile,dis\tan cetravelledwillbeequaltothemaximumrange. \\ R=\frac{u^2\sin 2\theta }{g} \\ u=20m/s \\ \theta ={15}^o \\ R=\frac{20\times 20\times \sin (2\times 15)}{10} \\ R=20m \end{gathered}$$