A bag contains 25 paise and 50 paise coins who's total value is Rs. 30. If the number of 25 paise coins is 4 times that of 50 paise coins, find the number of each type of coins.
Let number of 25 paise coins = x,
Number of 50 paise coins = y
x/4 + y/2 = 30
x + 2y = 120 …………….(i)
Also x = 4y (given)
Substituting the value of x in eq.(i), we get
4y + 2y = 120
6y = 120
y = 20
So x = 120 - 2y = 120 – 40 = 80
Therefore, number of 25 paise = 80 and number of 50 paise coins = 20.