A ball is projected horizontally from a tower with a velocity of 4m/s.Find the velocity of the ball after 0.70 seconds and acceleratio due to gravity=10m/s.
we know that
v = u + at
here,
u = initial horizontal velocity = 4 m/s
a = g = 10 m/s2
t = 0.70 s
so,
velocity after 0.7s will be
v = 4 + 10x0.70
thus,
v = 11 m/s