When a ball is thrown from a building having acceleration due to gravity $9.8 m / s^{2}$ . Then, the velocity of the ball is expressed as $v = 9.8 t$ . The velocity after $10 s e c o n d s$ is

9.8 m / s

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98 m / s

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Solution

The correct option is B $98 m / s$
Given $v = 9.8 t$ and $t = 10 s$

$v = 9.8 \times 10 = 98 m / s$

$∴$ velocity after $10 s$ will be $98 m / s$

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When a ball is thrown from a building having acceleration due to gravity 9.8m/s2. Then, the velocity of the ball is expressed as v=9.8t. The velocity after 10seconds is

The correct option is B 98m/sGiven v=9.8t and t=10 sv=9.8×10=98 m/s∴ velocity after 10 s will be 98 m/s

When a ball is thrown from a building having acceleration due to gravity $9.8 m / s^{2}$ . Then, the velocity of the ball is expressed as $v = 9.8 t$ . The velocity after $10 s e c o n d s$ is

The correct option is B $98 m / s$
Given $v = 9.8 t$ and $t = 10 s$

$v = 9.8 \times 10 = 98 m / s$

$∴$ velocity after $10 s$ will be $98 m / s$