Question

a body is thrown up with initial velocity 15m/s and stops after 5 seconds . calculate the acceleration and height reached

Answer 1

Here,

u = 15 ms^-1

t = 5 s

as the body stops

v = 0

Let h = height attained and a = acceleration

we know

here a is negative because the body is projected upward

v = u – at

=> 0 = 15 - 5a

=> a = 15/5 = 3ms^-2

Again,

h = ut – ½at²

=> h = 15×5 - ½×3×(5)²

=> h = 75 – 37.5

= 37.5 m

Acceleration = 3 ms^-2

Height attained = 37.5 m