A bullet of mass 20kg is found to pass two points 30mtrs aparts in 4 s.assuming the speed to be constant find its kinetic energy?

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Solution

kinetic energy is given by mv²/2
v=30m/4s=7.5m/s
kinetic energy=20(7.5)²/2=562.5kgm²/s²

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A bullet of mass 20kg is found to pass two points 30mtrs aparts in 4 s.assuming the speed to be constant find its kinetic energy?

kinetic energy is given by mv2/2v=30m/4s=7.5m/skinetic energy=20(7.5)2/2=562.5kgm2/s2

kinetic energy is given by mv²/2
v=30m/4s=7.5m/s
kinetic energy=20(7.5)²/2=562.5kgm²/s²