A copper wire has a diameter of 0.5mm and a resistivity of 1.6 ohm cm.How much of this wire would be necessary to make a 10 ohm coil?

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Solution

we know that
R = Ïl/A
or
l = AR/Ï

where
l = length of the wire = to be found
A = area of cross-section = Ï€(d/2)² = 3.14x(0.05/2)² = 1.96 x 10^-3 cm²
Ï = resistivity = 1.6 ohm.cm
R = resistance = 10 ohm

so,
l = (1.96 x 10^-3 x 10) / 1.6
or
l = 0.01225 cm = 0.125 mm

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A copper wire has a diameter of 0.5mm and a resistivity of 1.6 ohm cm.How much of this wire would be necessary to make a 10 ohm coil?

we know that R = Ïl/Aorl = AR/Ï wherel = length of the wire = to be foundA = area of cross-section = Ï€(d/2)2 = 3.14x(0.05/2)2 = 1.96 x 10-3 cm2Ï = resistivity = 1.6 ohm.cmR = resistance = 10 ohm so,l = (1.96 x 10-3 x 10) / 1.6orl = 0.01225 cm = 0.125 mm

we know that
R = Ïl/A
or
l = AR/Ï

where
l = length of the wire = to be found
A = area of cross-section = Ï€(d/2)² = 3.14x(0.05/2)² = 1.96 x 10^-3 cm²
Ï = resistivity = 1.6 ohm.cm
R = resistance = 10 ohm

so,
l = (1.96 x 10^-3 x 10) / 1.6
or
l = 0.01225 cm = 0.125 mm