a force of 10.5 n acts on a particle along a direction making an angle of 37 degree with the vertical. find the component of the force in the vertical direction

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Solution

Force of 10.5 N acts on a particle along a direction making an angle of 37 degree with the vertical.
as angle is made with vertical direction
Its vertical component will be , $F \cos (θ) = 10.5 \cos (37 °) = 10.5 \times 0.798 = 8.379 N$

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a force of 10.5 n acts on a particle along a direction making an angle of 37 degree with the vertical. find the component of the force in the vertical direction

Force of 10.5 N acts on a particle along a direction making an angle of 37 degree with the vertical. as angle is made with vertical direction Its vertical component will be , Fcosθ=10.5cos37°=10.5×0.798=8.379N

Force of 10.5 N acts on a particle along a direction making an angle of 37 degree with the vertical.
as angle is made with vertical direction
Its vertical component will be , $F \cos (θ) = 10.5 \cos (37 °) = 10.5 \times 0.798 = 8.379 N$