Question

a hemispherical bowl is made of 0.50cm thick brass .the inner radius of the bowl is 6 cm .find the outer curved surface area and volume of the bowl.

Answer 1

Inner radius of the hemispherical bowl;r = 6 cm
Thickness of the bowl = 0.50 cm
So, outer radius of the bowl;R = 6 cm + 0.50 cm = 6.50 cm
So outer curved surface area of bowl = $2{\mathrm{\pi R}}^2=2\times \frac{22}{7}\times {\left(6.50\right)}^2=265.571{\mathrm{cm}}^2$
And volume of the bowl = $\frac{2}{3}{\mathrm{\pi r}}^3=\frac{2}{3}\times \frac{22}{7}\times 6^3=452.571{\mathrm{cm}}^3$