A man with blood group A married a women with blood group B. they have a son with AB blood group and a daughter with blood group O. Work out the cross and show the possibility of such inheritance.

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Solution

The said parents have a daughter with O blood group, we can assume that both parents are heterozygous.
Hence,
Parental Phenotype - A group(genotype-AO) x B group(genotype-BO)
Parents: Heterozygous A Blood Father X Heterozygous B Blood Mother
Alleles: I ^Ai X I ^Bi
F1 progeny I ^Ai I ^AI ^BI ^Bi ii
The blood types of their children:
1/4 - AB Blood group.
1/4 - A Blood group.
1/4 - B Blood group.
1/4 - O Blood group

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