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Instantaneous Velocity

a moving body...

Question

a moving body travels the distance 's' with constant speed v1 distance 's' with uniform speed v2 prove that its average speed is 2v1 v2 by v1+v2

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Solution

t₁=d/v₁

t₂=d/v₂

average velocity=d+d/ d/v₁ +d/v₂

=(2d/dv₂+dv₁) v₁v₂

= 2v₁v₂/v₁+v₂

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a) A body covers first half of distance with a speed $V_{1}$ and second half of distance with a speed $V_{2}$	e) Average velocity is $\sqrt{\frac{g h}{2}}$
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d) A body freely is released from a height h	h) Average velocity is zero

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