Question

A neon-dioxygen mixture contains 70.6g dioxygen and 167.5g neon. If pressure of the ixture of gases in cylider is 25 bar, what is the partial pressure of dioygen and neon mixture.

Answer 1

Partial pressure = mole fraction of given gas x pure pressure.
Mole fraction = Number of moles of given gas / total number of moles.
Mole of dioxygen in mixture = given mass of dioxygen / molecular mass of dioxygen = 70.6 g/ 32 g = 2.2 moles
Moles of Neon in mixture = given mass of neon / atomic mass of neon = 167.5 g / 20 = 8.3 moles.
total number of moles = 2.2 + 8.3 = 10.5 mole
mole fraction of O₂ = 2.2 / 10.5 = 0.2
Mole fraction of neon = 8.3/ 10.5 = 0.8
partial pressure of di oxygen = 0.2 $\times$ 25 = 5 bar
Partial pressure of neon = $\times$ 25 = 20 bar