A rod of length L, along East-West direction is dropped from a height H.
if B be the magnetic field due to earth at that place and angle of dip isx, then what is the magnitude of induced emf across two ends of the rodwhen the rod reaches the earth?
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Solution
Given:
Length of rod: l
B be the magnetic field due to earth at that place and angle of dip is x.
that means the horizontal component of the magnetic field is B cos x
B cosx is the met field that will account for induced emf in the rod.
The velocity of rod after falling a distance of H = (2gH)1/2
Induced emf = Blv= Bsinx * l * (2gH)1/2