A ship sends out ultra sound that returns from the seabed and is detected after 4s. If the speed of ultrasound through sea water is 1550 m/s, find the distance of the seabed from the ship.

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Solution

Speed of ultrasound in sea water, v = 1550 m/s
Time taken by the ultrasound to hit the sea bed and return to the ship = 4 s
Therefore, time taken by the ultrasound to only reach the seabed = 4/2 = 2 s
Thus, the distance between the ship and the sea bed is,
s = speed X time
= > s = 1550 X 2 = 3100 m

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A ship sends out ultra sound that returns from the seabed and is detected after 4s. If the speed of ultrasound through sea water is 1550 m/s, find the distance of the seabed from the ship.

Speed of ultrasound in sea water, v = 1550 m/sTime taken by the ultrasound to hit the sea bed and return to the ship = 4 sTherefore, time taken by the ultrasound to only reach the seabed = 4/2 = 2 sThus, the distance between the ship and the sea bed is,s = speed X time= > s = 1550 X 2 = 3100 m

Speed of ultrasound in sea water, v = 1550 m/s
Time taken by the ultrasound to hit the sea bed and return to the ship = 4 s
Therefore, time taken by the ultrasound to only reach the seabed = 4/2 = 2 s
Thus, the distance between the ship and the sea bed is,
s = speed X time
= > s = 1550 X 2 = 3100 m