Question

a solution has been prepared by dissolving 0.4g of H2SO4 in 100 ml of the solution. calculate normality of the solution.

Answer 1

Normality of solution = number of equivalents of solute/ L
​Number of equivalent of H₂SO₄ = mass of H₂SO₄ in solution / equivalent mass of H₂SO₄
​Equivalent mass of H₂SO₄​​ = Molar mass / no. of inizable proton for acid
= 98 g/mol / 2 Eq mol^-1 = 49 g/Eq
​Number of equivalent of H₂SO₄ = 0.4 g/ 49 g Eq^-1 = 0.4/49 Eq
Normality = $\frac{\text{0.4}}{49}\text{Eq}\times \frac{1000{\text{ml L}}^{\text{-1}}}{100\text{ml}}$ = 0.08 Eq/L