Question

a solution of copper ii sulfate is electrolyzed for 16 minutes with a current of 1.5 amperes. what is the mass of copper deposited at cathode

Answer 1

We know,
Charge (Q) = Current (I) x Time (T)
= 1.5 A x (16 x 60) s
= 1440 C
Now,
$C{u}^{2+}\left(aq\right)+2e\to Cu\left(s\right)$

2 x 96500 C of charge deposits 1mole (63 g) of Cu
So, 1440 C of charge will deposit (63/193000) x 1440 = 0.47 g of Cu