Question

a stone is thrown vertically upward with a velocity 30ms^-1. if the acceleration due to gravity is 10ms^-2

what is the distance travelled by the particle during 1st second of its motion

Answer 1

$$\begin{gathered} u=30m/s \\ a=-g \\ dis\tan cetravelledinfirstsecond \\ s=ut+\frac{1}{2}a{t}^2 \\ s=30\left(1\right)-\frac{1}{2}\times 10\times 1\times 1 \\ s=25m \end{gathered}$$